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## Arithmetic: Percentage Test -4

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*Arithmetic: Percentage Test -4*.You scored %%SCORE%% out of %%TOTAL%%.You correct answer percentage: %%PERCENTAGE%% .Your performance has been rated as %%RATING%% Your answers are highlighted below.

Question 1 |

Atish saves 20% of his salary. His salary has increased by 20% and his expenditure has increased by 30%. What is the percentage change in his savings?

20% fall | |

4% fall | |

20% rise | |

4% rise |

Question 1 Explanation:

Let A be the income.

Expenditure = 0.8 A

Savings = 0.2 A => 20%

New income = 1.2 A (since 20% rise)

New expenditure = (0.8 A) X 1.3Â (Since 30% rise) = 1.04A

So, new savings = 1.2A â€“ 1.04A = 0.16A => 16%

% decrease = (20-16)/20 X 100 = 20%.

Expenditure = 0.8 A

Savings = 0.2 A => 20%

New income = 1.2 A (since 20% rise)

New expenditure = (0.8 A) X 1.3Â (Since 30% rise) = 1.04A

So, new savings = 1.2A â€“ 1.04A = 0.16A => 16%

% decrease = (20-16)/20 X 100 = 20%.

Question 2 |

The price of mangoes has increased by 25%. By what percent the consumption needs to be reduced so that the expense on mangoes remains the same?

25% | |

33.33% | |

20% | |

None |

Question 2 Explanation:

We solve this question using the principle of constancy.

Let original price = P

Increased Price- 1.25P

Original Consumption= C

Increased Consumption= I

It is given that expense is the same, that is:

1.25 x I = P x C

I=0.8 C

% decrease = {(1-0.8)/1} X 100 = 20%

Let original price = P

Increased Price- 1.25P

Original Consumption= C

Increased Consumption= I

It is given that expense is the same, that is:

1.25 x I = P x C

I=0.8 C

% decrease = {(1-0.8)/1} X 100 = 20%

Question 3 |

The side of a square is increased by 20%. The percentage change in its area is ___

20% | |

44% | |

36% | |

400% |

Question 3 Explanation:

Area of a square: side x side

% change in area = 1.2 X 1.2 (since area = side X side) = 1.44

= 44%.

% change in area = 1.2 X 1.2 (since area = side X side) = 1.44

= 44%.

Question 4 |

If the length of a rectangle is increased by 33.33%, by what percentage should the breadth be reduced to make the area same?

20%Â | |

33.33% | |

25%Â | |

None |

Question 4 Explanation:

Area of original rectangle: L X B

Area of new rectangle: 1.33L x b

Since the areas are the same:

1.33 L x b = L x B

b = Â¾ B

Decrease in breadth: 25%

Area of new rectangle: 1.33L x b

Since the areas are the same:

1.33 L x b = L x B

b = Â¾ B

Decrease in breadth: 25%

Question 5 |

10. In the 2013 Lok Sabha Election, two candidates, X and Y, contested from Delhi. A secured 64% of the votes and won 84000 votes. Find the total number of votes if 20% of votes polled were invalid.

300000 | |

375000 | |

350000 | |

400000 |

Question 5 Explanation:

X got 64% of the Valid Votes, V

Y got 36% of the Valid Votes, V

Difference: 28% of V = 84000

Therefore, V = 300000

Only 80% of the total votes are valid.

Therefore total votes = 300000 * (100/80) = 375000

Y got 36% of the Valid Votes, V

Difference: 28% of V = 84000

Therefore, V = 300000

Only 80% of the total votes are valid.

Therefore total votes = 300000 * (100/80) = 375000

Once you are finished, click the button below. Any items you have not completed will be marked incorrect.

There are 5 questions to complete.

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### Table of Contents

**Concept Articles**

**Exercises**

**Practice Tests**

### How to study this lesson?

It is actually simple to study this lesson.

Go through the given concepts and their corresponding exercises.

Then, solve the percentage practice tests and perfect the skills you have learnt