- This is an assessment test.
- These tests focus on the basics of Maths and are meant to indicate your preparation level for the subject.
- Kindly take the tests in this series with a pre-defined schedule.

## Basic Maths: Test 18

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*Basic Maths: Test 18*.You scored %%SCORE%% out of %%TOTAL%%.You correct answer percentage: %%PERCENTAGE%% .Your performance has been rated as %%RATING%% Your answers are highlighted below.

Question 1 |

Simplify:$ \displaystyle \frac{1+\frac{1}{2}}{1-\frac{1}{2}}\div \frac{3}{14}\left( \frac{2}{5}+\frac{3}{10} \right)\,of\,\frac{\frac{1}{2}+\frac{1}{3}}{\frac{1}{2}-\frac{1}{3}}$

$ \displaystyle 4$ | |

$ \displaystyle 37\frac{1}{2}$ | |

$ \displaystyle \frac{3}{2}$ | |

$ \displaystyle 18\frac{3}{8}$ |

Question 1 Explanation:

Question 2 |

Simplify $ \displaystyle \left[ 0.9\div \left\{ 2.3-3.2-\left( 7.1-5.4-3.5 \right) \right\} \right]$

0.18 | |

1.8 | |

1 | |

2.6 |

Question 2 Explanation:

$ \displaystyle \begin{array}{l}\left[ 0.9\div \left\{ 2.3-3.2-\left( 7.1-8.9 \right) \right\} \right]\\=\left[ 0.9\div \left\{ 2.3-3.2+1.8 \right\} \right]\\=\left[ 0.9\div 0.9 \right]\\=1\end{array}$

Question 3 |

The value of $ \displaystyle \frac{{{\left( 75.8 \right)}^{2}}-{{\left( 55.8 \right)}^{2}}}{40}$ is

20 | |

40 | |

65.8 | |

131.6 |

Question 3 Explanation:

$ \displaystyle \begin{array}{l}\frac{{{(75.8)}^{2}}-{{\left( 55.8 \right)}^{2}}}{40}\\=\frac{\left( 75.8-55.8 \right)\left( 75.8+55.8 \right)}{40}\\=\frac{20\times 131.6}{40}=65.8\end{array}$

Question 4 |

$ \displaystyle \frac{1}{4}+\left\{ 4\frac{3}{4}-\left( 3\frac{1}{6}-2\frac{1}{3} \right) \right\}$ is equal to

$ \displaystyle 3\frac{2}{3}$ | |

$ \displaystyle 1\frac{1}{4}$ | |

$ \displaystyle 4\frac{1}{6}$ | |

$ \displaystyle 1\frac{2}{3}$ |

Question 4 Explanation:

Expression

$ \displaystyle \begin{array}{l}=\frac{1}{4}+\left\{ \frac{19}{4}-\left( \frac{19}{6}-\frac{7}{3} \right)\, \right\}\\=\frac{1}{4}+\left\{ \frac{19}{4}-\left( \frac{19-14}{6} \right)\, \right\}\\=\frac{1}{4}+\left\{ \frac{19}{4}-\frac{5}{6} \right\}\\=\frac{1}{4}+\frac{19}{4}-\frac{5}{6}\\=\frac{50}{12}\\=4\frac{1}{6}\end{array}$

$ \displaystyle \begin{array}{l}=\frac{1}{4}+\left\{ \frac{19}{4}-\left( \frac{19}{6}-\frac{7}{3} \right)\, \right\}\\=\frac{1}{4}+\left\{ \frac{19}{4}-\left( \frac{19-14}{6} \right)\, \right\}\\=\frac{1}{4}+\left\{ \frac{19}{4}-\frac{5}{6} \right\}\\=\frac{1}{4}+\frac{19}{4}-\frac{5}{6}\\=\frac{50}{12}\\=4\frac{1}{6}\end{array}$

Question 5 |

If p represents a number, then the value of

*p*in $ \displaystyle 5\frac{3}{p}\times 3\frac{1}{2}=19$ is:7 | |

4 | |

6 | |

2 |

Question 5 Explanation:

$ \displaystyle \begin{array}{l}5\frac{3}{p}\times \frac{7}{2}=19\\\Rightarrow 5\frac{3}{p}=\frac{19\times 2}{7}\\\Rightarrow 5\frac{3}{p}=\frac{38}{7}=5\frac{3}{7}\\\Rightarrow p=7\end{array}$

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