- This is an assessment test.
- These tests focus on the basics of Maths and are meant to indicate your preparation level for the subject.
- Kindly take the tests in this series with a pre-defined schedule.

## Basic Maths: Test 50

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Question 1 |

A Washing Machine consumes 8 units of electricity in 30 minutes and a tube light, consumes 18 units of electricity in 6 hours, How much total unit of electricity will both Washing Machine and Tube light consume in 8 days if they run 10 hours a day?

1280 units | |

1528 units | |

1248 units | |

1520 units |

Question 1 Explanation:

Total electric consumption = (10 Ã—16Ã—8+3Ã—10Ã—8) units

= (1280 +240) units = 1520 units

= (1280 +240) units = 1520 units

Question 2 |

On Independence Day sweets were to be equally distributed among 400 children. But on that particular day, 100 children remained absent. Thus, each child got 3 sweets extra. How many sweets did each child get?

6 | |

12 | |

9 | |

Cannot be determined |

Question 2 Explanation:

Number of sweets for 100 absent children = 300 Ã— 3 =900

Therefore Number of sweets each students gets = $\frac{900}{100}+3=12$

Therefore Number of sweets each students gets = $\frac{900}{100}+3=12$

Question 3 |

There are some peacocks and some leopards in a forest. If the total number of animal heads in the forest are 858 and total number of animal legs are 1,746, what is the number of peacocks in the forest?

845 | |

833 | |

800 | |

None of these |

Question 3 Explanation:

If the number of peacocks in the forest be x, then number of leopards = 858 - x

Therefore

$\begin{align} & x\times 2+\left( 858-x \right)\times 4=1746 \\ & \Rightarrow 2x=3432-1746=1686 \\ & \Rightarrow x=\frac{1686}{2}=843 \\ \end{align}$

Therefore

$\begin{align} & x\times 2+\left( 858-x \right)\times 4=1746 \\ & \Rightarrow 2x=3432-1746=1686 \\ & \Rightarrow x=\frac{1686}{2}=843 \\ \end{align}$

Question 4 |

$\frac{139\times 139+135\times 135+18765}{139\times 139\times 139-135\times 135\times 135}$
is equal to

4 | |

270 | |

$\frac{1}{4}$ | |

$\frac{1}{270}$ |

Question 4 Explanation:

$\begin{align}
& =\frac{139\times 139+135\times 135+18765}{139\times 139\times 139-135\times 135\times 135} \\
& \left[ 139\times 135=18765 \right] \\
& Let\,139=a\,\,and\,\,135=b \\
& Therefore\,\,\,\exp ression\,\,=\frac{{{a}^{2}}+{{b}^{2}}+ab}{{{a}^{3}}+{{b}^{3}}} \\
& =\frac{{{a}^{2}}+{{b}^{2}}+ab}{\left( a-b \right)\left( {{a}^{2}}+{{b}^{2}}+ab \right)} \\
& =\frac{1}{a-b} \\
& =\frac{1}{139-135} \\
& =\frac{1}{4} \\
\end{align}$

Question 5 |

$\left( \frac{1}{7.9}+\frac{1}{9.11}+\frac{1}{11.13}+\frac{1}{13.15}+\frac{1}{15.17}+\frac{1}{17.19} \right)$
is equal to

6/133 | |

2/133 | |

12/133 | |

1/133 |

Question 5 Explanation:

\[\begin{align}
& \left( \frac{1}{7.9}+\frac{1}{9.11}+\frac{1}{11.13}+\frac{1}{13.15}+\frac{1}{15.17}+\frac{1}{17.19} \right) \\
& =\frac{1}{2}\left( \frac{2}{7.9}+\frac{2}{9.11}+\frac{2}{11.13}+\frac{2}{13.15}+\frac{2}{15.17}+\frac{2}{17.19} \right) \\
& =\frac{1}{2}\left( \frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}+\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+\frac{1}{15}-\frac{1}{17}+\frac{1}{17}-\frac{1}{19} \right) \\
& =\frac{1}{2}\left( \frac{1}{7}-\frac{1}{19} \right) \\
& =\frac{1}{2}\left( \frac{19-7}{133} \right) \\
& =\frac{1}{2}\times \frac{12}{133} \\
& =\frac{6}{133} \\
\end{align}\]

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