- This is an assessment test.
- These tests focus on the basics of Maths and are meant to indicate your preparation level for the subject.
- Kindly take the tests in this series with a pre-defined schedule.

## Basic Maths: Test 6

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*Basic Maths: Test 6*.You scored %%SCORE%% out of %%TOTAL%%.You correct answer percentage: %%PERCENTAGE%% .Your performance has been rated as %%RATING%% Your answers are highlighted below.

Question 1 |

What is the value of p ?

$\displaystyle \frac{p}{\sqrt{130}}=\frac{\sqrt{170}}{p}$

$\displaystyle \frac{p}{\sqrt{130}}=\frac{\sqrt{170}}{p}$

196 | |

12 | |

144 | |

16 |

Question 1 Explanation:

$ \displaystyle \begin{array}{l}\frac{p}{\sqrt{130}}=\frac{\sqrt{170}}{p}\\{{\left( p \right)}^{2}}=\sqrt{130}\times \sqrt{170}\\=11.40\times 13.03=148.542\\p=\sqrt{148.542}\approx 12\end{array}$

Question 2 |

$ \displaystyle If\,\,\,\,1.5p=0.04q$,then the value of $ \displaystyle \left( \frac{q-p}{q+p} \right)\,\,is:$

730/77 | |

73/77 | |

7.3/77 | |

703/77 |

Question 2 Explanation:

$ \displaystyle \begin{array}{l}1.5p=0.04q\\\Rightarrow \frac{p}{q}=\frac{0.04}{1.5}=\frac{4}{150}=\frac{2}{75}\\\therefore \,\,Expression\,\,=\frac{q-p}{q+p}=\frac{1-\frac{p}{q}}{1+\frac{p}{q}}\\=\frac{1-\frac{2}{75}}{1+\frac{2}{75}}=\frac{\frac{75-2}{75}}{\frac{75+2}{75}}\\=\frac{73}{75}\times \frac{75}{77}=\frac{73}{77}\end{array}$

Question 3 |

If $\displaystyle {{2}^{2p-1}}=\frac{1}{{{8}^{p-3}}}$,then the value of p is:

–1 | |

–2 | |

2 | |

3 |

Question 3 Explanation:

$ \displaystyle \begin{array}{l}{{2}^{2p-1}}=\frac{1}{{{8}^{p-3}}}={{8}^{-\left( p-3 \right)}}\\\Rightarrow {{2}^{2p-1}}={{8}^{3-p}}={{\left( {{2}^{3}} \right)}^{\left( 3-p \right)}}\\\Rightarrow {{2}^{2p-1}}={{2}^{9-3p}}\\\Rightarrow 2p-1=9-3p\\\Rightarrow 2p+3p=9+1\\\Rightarrow 5p=10\\\Rightarrow p=\frac{10}{5}=2\end{array}$

Question 4 |

$ \displaystyle 36865+12473+21045-44102=p$

114485 | |

28081 | |

26281 | |

114845 |

Question 4 Explanation:

$ \displaystyle \begin{array}{l}p=36865+12473+21045-44102\\=70383-44102=26281\end{array}$

Question 5 |

$\displaystyle 5328\times \frac{3}{4}\times \frac{2}{9}\times p=619$

0.69 | |

1.5 | |

0.2 | |

2.4 |

Question 5 Explanation:

$ \displaystyle \begin{array}{l}5328\times \frac{3}{4}\times \frac{2}{9}\times p=619\\\Rightarrow 888\times p=619\\\Rightarrow p=\frac{619}{888}=0.69\end{array}$

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