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## Geometry and Mensuration: Level 2 Test 2

Congratulations - you have completed Geometry and Mensuration: Level 2 Test 2.You scored %%SCORE%% out of %%TOTAL%%.You correct answer percentage: %%PERCENTAGE%% .Your performance has been rated as %%RATING%%
 Question 1
If the lengths of the sides of a triangle are in the ratio 4: 5: 6 and the in radius of the triangle is 3 cm, then the altitude of the triangle corresponding to the largest side as base is:
 A 7.5 cm B 6 cm C 10 cm D 8 cm
Question 1 Explanation:

Let the side of the triangle be 4x, 5x and 6x respectively. Semi-perimeter (s) =7.5x
The area = 3 x 7.5 sq. cm.
Thus, ½ X6x = 3 x 7.5
=> x= 7.5 cm
 Question 2
ABC is an isosceles right angled triangle with ∠B= 90o. On the sides AC and AB, two equilateral triangles ACD and ABE have been constructed. The ratio of areas of ABE and ACD is
 A 1: 3 B 2: 3 C 1: 2 D 1: √2
Question 2 Explanation:
The ratio of the hypotenuse AC to AB = 1:√2
Since both the triangles are equilateral their area are in the ratio
= 12:(√2)2 =1:2
 Question 3
Length of the floor of a rectangular auditorium is 6 metre more than the radius of a circle with a circumference of 572 m. The perimeter of the floor of the rectangular auditorium is 356 m. What will be cost of flooring the auditorium (only the floor of the auditorium), if the cost of flooring is Rs.121m2?
 A Rs.87, 954 B Rs.91, 236 C Rs.94, 284 D Rs.75, 490
Question 3 Explanation:
The radius = 572/2Π = 91 m
The length = 91+6 = 97 cm
The breadth = 356/2 – 91 = 81 m
Since the cost of flooring = Rs. 12 / m2
the total cost = Rs.97x81x12 = 94,284
 Question 4
O and C are respectively the orthocenter and circumcentre of an acute-angled triangle PQR. The points P and O are joined and produced to meet the side QR at S. If PQS= 60o and QCR= 130o, then RPS=
 A 30o B 35o C 100o D 60o
Question 4 Explanation:

∠PQS= 60o
∠QCR = 130, QC= CR .
Thus ∠CQR= ∠QRC = (180 -130)/2 =2
PQC = 60 -25 = 35, QPC = 35
Thus,
∠CPR+∠PRC + 60+35+25 = 180
Thus ∠RPS= 30 +∠CPS
Now, ∠QPS =90-60 = 30.
Thus ∠CPS = 35-30 = 5.
∠RPS = 35.
Correct option is (b)
 Question 5
ABC is a triangle, The bisectors of the internal angle B and external angle C intersect at D. If BDC= 50o, then ∠A is
 A 100o B 90o C 120o D 60o
Question 5 Explanation:
∠B+∠C = 2(90-50) = 80.
A = 180-80 = 100.
Correct option is (a)
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