Select Page

Question No. 1-3 are based on a set of conditions. In answering some of the questions, it may be useful to draw a rough diagram. Choose the response that most accurately and completely answers each question.

In a local pet store, seven puppies wait to be introduced to their new owners. The puppies, named Ashi, Burma, Cumin, Darton, Emeri, Faza, and Galzar, are all kept in two available pens. Pen 1 holds three puppies, and pen 2 holds four puppies.
If Galzar is kept in pen 1, then Darton is not kept in pen 2.
If Darton is not kept in pen 2, then Galzar is kept in pen 1. If Ashi is kept in pen 2, then Burma is not kept in pen 2. If Burma is kept in pen 1, then Ashi is not kept in pen 1.

Question 1 :  If Emeri and Faza are in different pens, then which of the following must NOT be true?
A. Faza shares a pen with Cumin.
B. Galzar shares a pen with Ashi.
C. Emeri is in a higher-numbered pen than Burma.
D. Burma shares pen 2 with Emeri and Darton.
E. Cumin is in a higher-numbered pen than Faza.

Question 2 :  Which of the following groups of puppies could be in pen 2?
A. Galzar, Darton, Cumin, Emeri.
B. Burma, Galzar, Ashi, Darton.
C. Ashi, Galzar, Emeri, Cumin.
D. Burma, Cumin, Emeri, Faza.
E. Galzar, Ashi, Faza, Emeri.

Question 3 :  If Emeri shares a pen with Faza, then which of the following MUST be true?
A. Galzar is in pen 1 with Darton.
B. Cumin is in pen 2.
C. Burma is in pen 2 and Faza is in pen 1.
D. Emeri is in pen 1.
E. Galzar snares a pen with Burma.

### Answers and Explanations

Answer 1: (E) Given that Emeri and Faza are in different pens. Option A can be true as: The puppies in pen 2 could be Emeri, Galzar, Darton and Ashi. The puppies in pen 1 could be Faza, Cumin and Burma. Option B can be true as: The puppies in pen 2 could be Emeri, Galzar, Darton and Ashi. The puppies in pen 1 could be Faza, Cumin and Burma. Option C can be true as: The puppies in pen 2 could be Emeri, Galzar, Darton and Ashi. The puppies in pen 1 could be Faza, Cumin and Burma. Option D can be true as: The puppies in pen 2 could be Emeri, Galzar, Darton and Burma The puppies in pen 1 could be Faza, Cumin and Ashi. Option E cannot be true as it means Cumin is in pen 2 and Faza is in pen 1. So, Emeri is in pen 2 along with Cumin. Darton and Burma have to be in different pens. But Galzar and Darton have to be together. Hence, this cannot be true.

Option A: The given group of puppies cannot be in pen 2 as Burma and Ashley cannot be together in pen 1. Option B: The given group of puppies cannot be in pen 2 as Burma and Ashi cannot be together in pen 2. Option C: The given group of puppies cannot be in pen 2 as if Darton is not kept in pen 2, then Galzar is kept in pen 1 and in this case Galzar is put in pen 2. Option D: The given group of puppies can be in pen 2. Option E: The given group of puppies cannot be in pen 2 as if Darton is not kept in pen 2, then Galzar is kept in pen 1 and in this case Galzar is put in pen 2.

Given that Emeri shares a pen with Faza. Option A is not necessarily true as: The puppies in pen 1 could be Emeri, Faza and Burma. The puppies in pen 2 could be Galzar, Darton, Ashi and Cumin.

Option B is necessarily true as Galzar and Darton have to be together and given that Emeri and Faza are also together. Also, Ashi and Burma have to be in different pens. So, Cumin must be in pen 2, which has four puppies.

Option C is not necessarily true as: The puppies in pen 1 could be Galzar, Darton and Ashi. The puppies in pen 2 could be Emeri, Faza, Cumin and Burma.

Option D is not necessarily true as: The puppies in pen 1 could be Galzar, Darton and Ashi. The puppies in pen 2 could be Emeri, Faza, Cumin and Burma.

Option E is not necessarily true as: The puppies in pen 1 could be Galzar, Darton and Ahlen. The puppies in pen 2 could be Emeri, Faza, Cumin and Burma.